**Hello Aspirants,**

Welcome to Online Quant Section in AffairsCloud.com. We are starting **IBPS Clerk course 2015 **and we are creating sample questions in **Quantitative Aptitude** section, type of which will be asked in IBPS Clerk Main Exam.

**Stratus – IBPS Clerk Course 2015 **

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**5x**^{2}+ 17x – 12 = 0, 5y^{2}– 18y + 9 = 0

A) x > y

B) x < y

C) x ≥ y

D) x ≤ y

E) x = y or relationship cannot be determined

**D) x ≤ y**

Explanation:

5x^{2}+ 17x – 12 = 0

5x^{2}+ 20x – 3x – 12 = 0

Gives x = -4, 3/5

5y^{2}– 18y + 9 = 0

5y^{2}– 15y – 3y + 9 = 0

Gives y = 3/5, 3

Put on number line

-4 3/5 3**3x**^{2}+ 14x + 8 = 0, 3y^{2}– 4y – 4 = 0

A) x > y

B) x < y

C) x ≥ y

D) x ≤ y

E) x = y or relationship cannot be determined

**D) x ≤ y**

Explanation:

3x^{2}+ 14x + 8 = 0

3x^{2}+ 12x + 2x + 8 = 0

Gives x = -4, -2/3

3y^{2}– 4y – 4 = 0

3y^{2}– 6y + 2y – 4 = 0

Gives y = -2/3, 2

Put on number line

-4 -2/3 2**x = √1849, y**^{2}= 1156

A) x > y

B) x < y

C) x ≥ y

D) x ≤ y

E) x = y or relationship cannot be determined

**A) x > y**

Explanation:

x = √1849

Gives, x = 43

y^{2}= 1156

Gives y = -34, 34

Put on number line

-34 34 43**4x + 5y = 75, 5x + 4y = 69**

A) x > y

B) x < y

C) x ≥ y

D) x ≤ y

E) x = y or relationship cannot be determined

**B) x < y**

Explanation:

Multiply first equation by 4 and second by 5 and subtract

16x + 20y = 300, 25x + 20y = 345

Subtract

-9x = -45

Gives x = 5

Put x = 5 in one of the given equations, and find y

4(5) + 5y = 75

Gives y = 11

Put on number line

5 11**6x**^{2}– 5x – 6 = 0, 3y^{2}– 7y – 6 = 0

A) x > y

B) x < y

C) x ≥ y

D) x ≤ y

E) x = y or relationship cannot be determined

**E) x = y or relationship cannot be determined**

Explanation:

6x^{2}– 5x – 6 = 0

6x^{2}– 9x + 4x – 6 = 0

Gives, x = -2/3, 3/2

3y^{2}– 7y – 6 = 0

3y^{2}– 9y + 2y – 6 = 0

Gives, y = -2/3, 3

Put on number line

-2/3 3/2 3

When x = -2/3, x ≤ y

When x = 3/2, x > y(-2/3) and also x < y(3)

No so relationship.

** DIRECTIONS (6 – 10) : These questions are to be answered on the basis of the pie chart given below showing how a person’s monthly salary is distributed over different expense heads. **

**For a person, whose monthly salary is Rs 6,000, how many items are there on which he has to spend more than Rs 1,000 per month ?**

A) None

B) 1

C) 2

D) 3

E) 4

**C) 2**

Explanation:

Shortcut-

(x/100)*6000 = 1000, gives x = 16.67%

So the ones having more expense % than 16.67% which is house rent and savings**The annual saving for such a person will be approximately:**

A) Rs 15050

B) Rs 16560

C) Rs 15500

D) Rs 16500

E) None of these

**B) Rs 16560**

Explanation:

Savings over month = (23/100)*6000 = 1380

So annually = 1380*12 = 16560

**The monthly salary for a person who follows the same expense pattern, but has a petrol expense of Rs 500 per month is**

A) Rs 2500

B) Rs 3500

C) Rs 5000

D) Rs 6500

E) Rs 6600

**C) Rs 5000**

Explanation:

(10/100)*x = 500**If the monthly salary of a person is Rs 12,000, then approximately by how much % is his expenses on entertainment more than on clothes?**

A) 96%

B) 114%

C) 120%

D) 83%

E) None of these

**B) 114%**

Explanation:

Exp. on enter. = (15/100)*12,000 = 1800

Exp. on clothes = (7/100)*12,000 = 840

Required % = (1800-840)/840 * 100**The angle made at the centre of the pie chart by the sector representing the expense on food is :**

A) 30^{o}

B) 45^{o}

C) 54^{o}

D) 75^{o}

E) 90^{o}

**C) 54**^{o}

Explanation:

(15/100)*360 = 54

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